-32f^2-80f-50=0

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Solution for -32f^2-80f-50=0 equation: 



-32f^2-80f-50=0

a = -32; b = -80; c = -50;
Δ = b2-4ac
Δ = -802-4·(-32)·(-50)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{80}{-64}=-1+1/4$

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